pointers-memory · intermediate · ~22 min
Compute total size, allocate once, and copy — avoid the trap of growing buffers in a loop with `realloc` for no reason.
Join three strings into one freshly allocated string, sizing the buffer correctly in a single allocation.
Implement char *concat3(const char *a, const char *b, const char *c) that returns a newly allocated string equal to a followed by b followed by c. No main — the grader calls it.
Three non-NULL, NUL-terminated strings a, b, c (any of them may be empty).
A malloc-ed NUL-terminated string holding the concatenation. The caller frees it. Return NULL if allocation fails.
concat3("foo", "-", "bar") -> "foo-bar"
concat3("", "", "") -> ""
concat3("abc", "def", "ghi") -> "abcdefghi"
"" (still a valid allocation, just the NUL byte).+1 for the terminator.Transfer exercise: apply the lesson to a complete function contract.
Three non-NULL, NUL-terminated strings a, b, c (any of them may be empty).
A malloc-ed NUL-terminated string holding the concatenation. The caller frees it. Return NULL if allocation fails.
Three non-NULL live terminated strings, borrowed and unmodified. Return one owned terminated concatenation, or NULL if combined size overflows or allocation fails.
#include <stdlib.h>
#include <string.h>
char *concat3(const char *a, const char *b, const char *c) {
/* TODO */
return NULL;
}
Counting only two inputs, omitting the terminator, or unchecked length addition.
Any or all of the three strings empty; one byte for an all-empty result; combined-size overflow.
O(strlen(a) + strlen(b)).
Solve this exercise in the browser editor — compile and run against the test harness, no setup required.